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3x-2(3x+3)=-(3x+6)
We move all terms to the left:
3x-2(3x+3)-(-(3x+6))=0
We multiply parentheses
3x-6x-(-(3x+6))-6=0
We calculate terms in parentheses: -(-(3x+6)), so:We add all the numbers together, and all the variables
-(3x+6)
We get rid of parentheses
-3x-6
Back to the equation:
-(-3x-6)
-3x-(-3x-6)-6=0
We get rid of parentheses
-3x+3x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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