3x-2(3-7)+5=2-4(3x+7)

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Solution for 3x-2(3-7)+5=2-4(3x+7) equation: 



3x-2(3-7)+5=2-4(3x+7)

We move all terms to the left:

3x-2(3-7)+5-(2-4(3x+7))=0

We add all the numbers together, and all the variables

3x-(2-4(3x+7))+5-2(-4)=0

We add all the numbers together, and all the variables

3x-(2-4(3x+7))+13=0



We calculate terms in parentheses: -(2-4(3x+7)), so:

2-4(3x+7)

determiningTheFunctionDomain
-4(3x+7)+2

We multiply parentheses

-12x-28+2

We add all the numbers together, and all the variables

-12x-26

Back to the equation:

-(-12x-26)



We get rid of parentheses

3x+12x+26+13=0

We add all the numbers together, and all the variables

15x+39=0

We move all terms containing x to the left, all other terms to the right

15x=-39

x=-39/15

x=-2+3/5

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