3x-2(2x-5)=2(2x-5)=2(x+3)-8

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Solution for 3x-2(2x-5)=2(2x-5)=2(x+3)-8 equation: 



3x-2(2x-5)=2(2x-5)=2(x+3)-8

We move all terms to the left:

3x-2(2x-5)-(2(2x-5))=0

We multiply parentheses

3x-4x-(2(2x-5))+10=0



We calculate terms in parentheses: -(2(2x-5)), so:

2(2x-5)

We multiply parentheses

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

-1x-(4x-10)+10=0

We get rid of parentheses

-1x-4x+10+10=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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