3x-2(2-3x)=3(x-3)-19

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Solution for 3x-2(2-3x)=3(x-3)-19 equation: 



3x-2(2-3x)=3(x-3)-19

We move all terms to the left:

3x-2(2-3x)-(3(x-3)-19)=0

We add all the numbers together, and all the variables

3x-2(-3x+2)-(3(x-3)-19)=0

We multiply parentheses

3x+6x-(3(x-3)-19)-4=0



We calculate terms in parentheses: -(3(x-3)-19), so:

3(x-3)-19

We multiply parentheses

3x-9-19

We add all the numbers together, and all the variables

3x-28

Back to the equation:

-(3x-28)



We add all the numbers together, and all the variables

9x-(3x-28)-4=0

We get rid of parentheses

9x-3x+28-4=0

We add all the numbers together, and all the variables

6x+24=0

We move all terms containing x to the left, all other terms to the right

6x=-24

x=-24/6

x=-4

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