3x-2(-2x-2)=-7+4(4x-x)

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Solution for 3x-2(-2x-2)=-7+4(4x-x) equation: 



3x-2(-2x-2)=-7+4(4x-x)

We move all terms to the left:

3x-2(-2x-2)-(-7+4(4x-x))=0

We add all the numbers together, and all the variables

3x-2(-2x-2)-(-7+4(+3x))=0

We multiply parentheses

3x+4x-(-7+4(+3x))+4=0



We calculate terms in parentheses: -(-7+4(+3x)), so:

-7+4(+3x)

determiningTheFunctionDomain
4(+3x)-7

We multiply parentheses

12x-7

Back to the equation:

-(12x-7)



We add all the numbers together, and all the variables

7x-(12x-7)+4=0

We get rid of parentheses

7x-12x+7+4=0

We add all the numbers together, and all the variables

-5x+11=0

We move all terms containing x to the left, all other terms to the right

-5x=-11

x=-11/-5

x=2+1/5

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