3x-2(-2-2)=-7+4(4x-4)

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Solution for 3x-2(-2-2)=-7+4(4x-4) equation: 



3x-2(-2-2)=-7+4(4x-4)

We move all terms to the left:

3x-2(-2-2)-(-7+4(4x-4))=0

We add all the numbers together, and all the variables

3x-(-7+4(4x-4))-2(-4)=0

We add all the numbers together, and all the variables

3x-(-7+4(4x-4))+8=0



We calculate terms in parentheses: -(-7+4(4x-4)), so:

-7+4(4x-4)

determiningTheFunctionDomain
4(4x-4)-7

We multiply parentheses

16x-16-7

We add all the numbers together, and all the variables

16x-23

Back to the equation:

-(16x-23)



We get rid of parentheses

3x-16x+23+8=0

We add all the numbers together, and all the variables

-13x+31=0

We move all terms containing x to the left, all other terms to the right

-13x=-31

x=-31/-13

x=2+5/13

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