3x-1=3(x+2)-x

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Solution for 3x-1=3(x+2)-x equation: 



3x-1=3(x+2)-x

We move all terms to the left:

3x-1-(3(x+2)-x)=0



We calculate terms in parentheses: -(3(x+2)-x), so:

3(x+2)-x

We add all the numbers together, and all the variables

-1x+3(x+2)

We multiply parentheses

-1x+3x+6

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

3x-2x-6-1=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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