3x-1=1/2x+5

Solution for 3x-1=1/2x+5 equation:

3x-1=1/2x+5

We move all terms to the left:

3x-1-(1/2x+5)=0


Domain of the equation: 2x+5)!=0

x∈R


We get rid of parentheses

3x-1/2x-5-1=0

We multiply all the terms by the denominator


3x*2x-5*2x-1*2x-1=0

Wy multiply elements

6x^2-10x-2x-1=0

We add all the numbers together, and all the variables

6x^2-12x-1=0

a = 6; b = -12; c = -1;
Δ = b2-4ac
Δ = -122-4·6·(-1)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{42}}{2*6}=\frac{12-2\sqrt{42}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{42}}{2*6}=\frac{12+2\sqrt{42}}{12}
$