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3x-1=-1/2x+6
We move all terms to the left:
3x-1-(-1/2x+6)=0
Domain of the equation: 2x+6)!=0We get rid of parentheses
x∈R
3x+1/2x-6-1=0
We multiply all the terms by the denominator
3x*2x-6*2x-1*2x+1=0
Wy multiply elements
6x^2-12x-2x+1=0
We add all the numbers together, and all the variables
6x^2-14x+1=0
a = 6; b = -14; c = +1;
Δ = b2-4ac
Δ = -142-4·6·1
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{43}}{2*6}=\frac{14-2\sqrt{43}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{43}}{2*6}=\frac{14+2\sqrt{43}}{12} $
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