3x-16+7x-38=4x-12

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Solution for 3x-16+7x-38=4x-12 equation: 



3x-16+7x-38=4x-12

We move all terms to the left:

3x-16+7x-38-(4x-12)=0

We add all the numbers together, and all the variables

10x-(4x-12)-54=0

We get rid of parentheses

10x-4x+12-54=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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