3x-15=7(x+1)-4(x-4)

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Solution for 3x-15=7(x+1)-4(x-4) equation: 



3x-15=7(x+1)-4(x-4)

We move all terms to the left:

3x-15-(7(x+1)-4(x-4))=0



We calculate terms in parentheses: -(7(x+1)-4(x-4)), so:

7(x+1)-4(x-4)

We multiply parentheses

7x-4x+7+16

We add all the numbers together, and all the variables

3x+23

Back to the equation:

-(3x+23)



We get rid of parentheses

3x-3x-23-15=0

We add all the numbers together, and all the variables

-38!=0

There is no solution for this equation

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