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3x-15=2x(x-5)
We move all terms to the left:
3x-15-(2x(x-5))=0
We calculate terms in parentheses: -(2x(x-5)), so:We get rid of parentheses
2x(x-5)
We multiply parentheses
2x^2-10x
Back to the equation:
-(2x^2-10x)
-2x^2+3x+10x-15=0
We add all the numbers together, and all the variables
-2x^2+13x-15=0
a = -2; b = 13; c = -15;
Δ = b2-4ac
Δ = 132-4·(-2)·(-15)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*-2}=\frac{-20}{-4} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*-2}=\frac{-6}{-4} =1+1/2 $
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