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3x-14/3x-7=11
We move all terms to the left:
3x-14/3x-7-(11)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
3x-14/3x-18=0
We multiply all the terms by the denominator
3x*3x-18*3x-14=0
Wy multiply elements
9x^2-54x-14=0
a = 9; b = -54; c = -14;
Δ = b2-4ac
Δ = -542-4·9·(-14)
Δ = 3420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3420}=\sqrt{36*95}=\sqrt{36}*\sqrt{95}=6\sqrt{95}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-6\sqrt{95}}{2*9}=\frac{54-6\sqrt{95}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+6\sqrt{95}}{2*9}=\frac{54+6\sqrt{95}}{18} $
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