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3x-10=2x(x-2)
We move all terms to the left:
3x-10-(2x(x-2))=0
We calculate terms in parentheses: -(2x(x-2)), so:We get rid of parentheses
2x(x-2)
We multiply parentheses
2x^2-4x
Back to the equation:
-(2x^2-4x)
-2x^2+3x+4x-10=0
We add all the numbers together, and all the variables
-2x^2+7x-10=0
a = -2; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·(-2)·(-10)
Δ = -31
Delta is less than zero, so there is no solution for the equation
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