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3x-10=2(x+1/12)
We move all terms to the left:
3x-10-(2(x+1/12))=0
We add all the numbers together, and all the variables
3x-(2(+x+1/12))-10=0
We multiply all the terms by the denominator
3x*12))-(2(+x+1-10*12))=0
We add all the numbers together, and all the variables
3x*12))-(2(x-119))=0
We add all the numbers together, and all the variables
3x*12))-(2(x=0
Wy multiply elements
36x^2=0
a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{72}=0$
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