3x-100+3x=10+2x-50+20

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Solution for 3x-100+3x=10+2x-50+20 equation: 



3x-100+3x=10+2x-50+20

We move all terms to the left:

3x-100+3x-(10+2x-50+20)=0

We add all the numbers together, and all the variables

3x+3x-(2x-20)-100=0

We add all the numbers together, and all the variables

6x-(2x-20)-100=0

We get rid of parentheses

6x-2x+20-100=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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