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3x-10+x=2(2x-5)
We move all terms to the left:
3x-10+x-(2(2x-5))=0
We add all the numbers together, and all the variables
4x-(2(2x-5))-10=0
We calculate terms in parentheses: -(2(2x-5)), so:We get rid of parentheses
2(2x-5)
We multiply parentheses
4x-10
Back to the equation:
-(4x-10)
4x-4x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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