3x-10+4x=-2(x-4)+8

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Solution for 3x-10+4x=-2(x-4)+8 equation: 



3x-10+4x=-2(x-4)+8

We move all terms to the left:

3x-10+4x-(-2(x-4)+8)=0

We add all the numbers together, and all the variables

7x-(-2(x-4)+8)-10=0



We calculate terms in parentheses: -(-2(x-4)+8), so:

-2(x-4)+8

We multiply parentheses

-2x+8+8

We add all the numbers together, and all the variables

-2x+16

Back to the equation:

-(-2x+16)



We get rid of parentheses

7x+2x-16-10=0

We add all the numbers together, and all the variables

9x-26=0

We move all terms containing x to the left, all other terms to the right

9x=26

x=26/9

x=2+8/9

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