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3x-1/5x=2
We move all terms to the left:
3x-1/5x-(2)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
3x*5x-2*5x-1=0
Wy multiply elements
15x^2-10x-1=0
a = 15; b = -10; c = -1;
Δ = b2-4ac
Δ = -102-4·15·(-1)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{10}}{2*15}=\frac{10-4\sqrt{10}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{10}}{2*15}=\frac{10+4\sqrt{10}}{30} $
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