3x-1-8x-4=16x-12

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Solution for 3x-1-8x-4=16x-12 equation: 



3x-1-8x-4=16x-12

We move all terms to the left:

3x-1-8x-4-(16x-12)=0

We add all the numbers together, and all the variables

-5x-(16x-12)-5=0

We get rid of parentheses

-5x-16x+12-5=0

We add all the numbers together, and all the variables

-21x+7=0

We move all terms containing x to the left, all other terms to the right

-21x=-7

x=-7/-21

x=1/3

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