3x-1+2(5-x)-2=4(x+2)-2x-1

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Solution for 3x-1+2(5-x)-2=4(x+2)-2x-1 equation: 



3x-1+2(5-x)-2=4(x+2)-2x-1

We move all terms to the left:

3x-1+2(5-x)-2-(4(x+2)-2x-1)=0

We add all the numbers together, and all the variables

3x+2(-1x+5)-(4(x+2)-2x-1)-1-2=0

We add all the numbers together, and all the variables

3x+2(-1x+5)-(4(x+2)-2x-1)-3=0

We multiply parentheses

3x-2x-(4(x+2)-2x-1)+10-3=0



We calculate terms in parentheses: -(4(x+2)-2x-1), so:

4(x+2)-2x-1

We add all the numbers together, and all the variables

-2x+4(x+2)-1

We multiply parentheses

-2x+4x+8-1

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

x-(2x+7)+7=0

We get rid of parentheses

x-2x-7+7=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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