3x-1+(3x-3)=62

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Solution for 3x-1+(3x-3)=62 equation:



3x-1+(3x-3)=62
We move all terms to the left:
3x-1+(3x-3)-(62)=0
We add all the numbers together, and all the variables
3x+(3x-3)-63=0
We get rid of parentheses
3x+3x-3-63=0
We add all the numbers together, and all the variables
6x-66=0
We move all terms containing x to the left, all other terms to the right
6x=66
x=66/6
x=11

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