3x-(x-2)=(2x-1)-(3x+9)=

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Solution for 3x-(x-2)=(2x-1)-(3x+9)= equation: 



3x-(x-2)=(2x-1)-(3x+9)=

We move all terms to the left:

3x-(x-2)-((2x-1)-(3x+9))=0

We get rid of parentheses

3x-x-((2x-1)-(3x+9))+2=0



We calculate terms in parentheses: -((2x-1)-(3x+9)), so:

(2x-1)-(3x+9)

We get rid of parentheses

2x-3x-1-9

We add all the numbers together, and all the variables

-1x-10

Back to the equation:

-(-1x-10)



We add all the numbers together, and all the variables

2x-(-1x-10)+2=0

We get rid of parentheses

2x+1x+10+2=0

We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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