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3x-(x-11)=6-3(x+5)
We move all terms to the left:
3x-(x-11)-(6-3(x+5))=0
We get rid of parentheses
3x-x-(6-3(x+5))+11=0
We calculate terms in parentheses: -(6-3(x+5)), so:We add all the numbers together, and all the variables
6-3(x+5)
determiningTheFunctionDomain -3(x+5)+6
We multiply parentheses
-3x-15+6
We add all the numbers together, and all the variables
-3x-9
Back to the equation:
-(-3x-9)
2x-(-3x-9)+11=0
We get rid of parentheses
2x+3x+9+11=0
We add all the numbers together, and all the variables
5x+20=0
We move all terms containing x to the left, all other terms to the right
5x=-20
x=-20/5
x=-4
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