3x-(x+5)=6+(x+1)

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Solution for 3x-(x+5)=6+(x+1) equation: 



3x-(x+5)=6+(x+1)

We move all terms to the left:

3x-(x+5)-(6+(x+1))=0

We get rid of parentheses

3x-x-(6+(x+1))-5=0



We calculate terms in parentheses: -(6+(x+1)), so:

6+(x+1)

determiningTheFunctionDomain
(x+1)+6

We get rid of parentheses

x+1+6

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We add all the numbers together, and all the variables

2x-(x+7)-5=0

We get rid of parentheses

2x-x-7-5=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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