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3x-(x+5)=4(2x-20)
We move all terms to the left:
3x-(x+5)-(4(2x-20))=0
We get rid of parentheses
3x-x-(4(2x-20))-5=0
We calculate terms in parentheses: -(4(2x-20)), so:We add all the numbers together, and all the variables
4(2x-20)
We multiply parentheses
8x-80
Back to the equation:
-(8x-80)
2x-(8x-80)-5=0
We get rid of parentheses
2x-8x+80-5=0
We add all the numbers together, and all the variables
-6x+75=0
We move all terms containing x to the left, all other terms to the right
-6x=-75
x=-75/-6
x=12+1/2
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