3x-(x+5)/5=12+(3-2x)/4

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Solution for 3x-(x+5)/5=12+(3-2x)/4 equation: 



3x-(x+5)/5=12+(3-2x)/4

We move all terms to the left:

3x-(x+5)/5-(12+(3-2x)/4)=0

We add all the numbers together, and all the variables

3x-(x+5)/5-(12+(-2x+3)/4)=0

We calculate fractions


3x+(-x)/()+(-(12+(-2x+3)*5)/()=0



We calculate terms in parentheses: +(-(12+(-2x+3)*5)/(), so:

-(12+(-2x+3)*5)/(

We multiply all the terms by the denominator


-(12+(-2x+3)*5)



We calculate terms in parentheses: -(12+(-2x+3)*5), so:

12+(-2x+3)*5

determiningTheFunctionDomain
(-2x+3)*5+12

We multiply parentheses

-10x+15+12

We add all the numbers together, and all the variables

-10x+27

Back to the equation:

-(-10x+27)



We get rid of parentheses

10x-27

Back to the equation:

+(10x-27)



We add all the numbers together, and all the variables

3x+(-1x)/()+(10x-27)=0

We get rid of parentheses

3x+(-1x)/()+10x-27=0

We multiply all the terms by the denominator


3x*()+(-1x)+10x*()-27*()=0

We add all the numbers together, and all the variables

3x*()+(-1x)+10x*()=0

We get rid of parentheses

3x*()-1x+10x*()=0

We add all the numbers together, and all the variables

-1x+3x*()+10x*()=0

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