3x-(x+4)=2(x-7)+10

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Solution for 3x-(x+4)=2(x-7)+10 equation:


Simplifying
3x + -1(x + 4) = 2(x + -7) + 10

Reorder the terms:
3x + -1(4 + x) = 2(x + -7) + 10
3x + (4 * -1 + x * -1) = 2(x + -7) + 10
3x + (-4 + -1x) = 2(x + -7) + 10

Reorder the terms:
-4 + 3x + -1x = 2(x + -7) + 10

Combine like terms: 3x + -1x = 2x
-4 + 2x = 2(x + -7) + 10

Reorder the terms:
-4 + 2x = 2(-7 + x) + 10
-4 + 2x = (-7 * 2 + x * 2) + 10
-4 + 2x = (-14 + 2x) + 10

Reorder the terms:
-4 + 2x = -14 + 10 + 2x

Combine like terms: -14 + 10 = -4
-4 + 2x = -4 + 2x

Add '4' to each side of the equation.
-4 + 4 + 2x = -4 + 4 + 2x

Combine like terms: -4 + 4 = 0
0 + 2x = -4 + 4 + 2x
2x = -4 + 4 + 2x

Combine like terms: -4 + 4 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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