3x-(x+(4x+1)+3)=6

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Solution for 3x-(x+(4x+1)+3)=6 equation: 



3x-(x+(4x+1)+3)=6

We move all terms to the left:

3x-(x+(4x+1)+3)-(6)=0



We calculate terms in parentheses: -(x+(4x+1)+3), so:

x+(4x+1)+3

We get rid of parentheses

x+4x+1+3

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We get rid of parentheses

3x-5x-4-6=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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