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3x-(6-x)=6x-2(x+3)
We move all terms to the left:
3x-(6-x)-(6x-2(x+3))=0
We add all the numbers together, and all the variables
3x-(-1x+6)-(6x-2(x+3))=0
We get rid of parentheses
3x+1x-(6x-2(x+3))-6=0
We calculate terms in parentheses: -(6x-2(x+3)), so:We add all the numbers together, and all the variables
6x-2(x+3)
We multiply parentheses
6x-2x-6
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
4x-(4x-6)-6=0
We get rid of parentheses
4x-4x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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