3x-(5x-2(x-3)-2)=3(1-4x)

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Solution for 3x-(5x-2(x-3)-2)=3(1-4x) equation: 



3x-(5x-2(x-3)-2)=3(1-4x)

We move all terms to the left:

3x-(5x-2(x-3)-2)-(3(1-4x))=0

We add all the numbers together, and all the variables

3x-(5x-2(x-3)-2)-(3(-4x+1))=0



We calculate terms in parentheses: -(5x-2(x-3)-2), so:

5x-2(x-3)-2

We multiply parentheses

5x-2x+6-2

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)





We calculate terms in parentheses: -(3(-4x+1)), so:

3(-4x+1)

We multiply parentheses

-12x+3

Back to the equation:

-(-12x+3)



We get rid of parentheses

3x-3x+12x-4-3=0

We add all the numbers together, and all the variables

12x-7=0

We move all terms containing x to the left, all other terms to the right

12x=7

x=7/12

x=7/12

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