3x-(3-8x)-5=x-(-6-2x)+14

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Solution for 3x-(3-8x)-5=x-(-6-2x)+14 equation: 



3x-(3-8x)-5=x-(-6-2x)+14

We move all terms to the left:

3x-(3-8x)-5-(x-(-6-2x)+14)=0

We add all the numbers together, and all the variables

3x-(-8x+3)-(x-(-2x-6)+14)-5=0

We get rid of parentheses

3x+8x-(x-(-2x-6)+14)-3-5=0



We calculate terms in parentheses: -(x-(-2x-6)+14), so:

x-(-2x-6)+14

We get rid of parentheses

x+2x+6+14

We add all the numbers together, and all the variables

3x+20

Back to the equation:

-(3x+20)



We add all the numbers together, and all the variables

11x-(3x+20)-8=0

We get rid of parentheses

11x-3x-20-8=0

We add all the numbers together, and all the variables

8x-28=0

We move all terms containing x to the left, all other terms to the right

8x=28

x=28/8

x=3+1/2

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