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3x-(2x+1)=3(x+1)
We move all terms to the left:
3x-(2x+1)-(3(x+1))=0
We get rid of parentheses
3x-2x-(3(x+1))-1=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
x-(3x+3)-1=0
We get rid of parentheses
x-3x-3-1=0
We add all the numbers together, and all the variables
-2x-4=0
We move all terms containing x to the left, all other terms to the right
-2x=4
x=4/-2
x=-2
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