3x-(-4-2x)+7x=-10+2(16-3x)

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Solution for 3x-(-4-2x)+7x=-10+2(16-3x) equation: 



3x-(-4-2x)+7x=-10+2(16-3x)

We move all terms to the left:

3x-(-4-2x)+7x-(-10+2(16-3x))=0

We add all the numbers together, and all the variables

3x-(-2x-4)+7x-(-10+2(-3x+16))=0

We add all the numbers together, and all the variables

10x-(-2x-4)-(-10+2(-3x+16))=0

We get rid of parentheses

10x+2x-(-10+2(-3x+16))+4=0



We calculate terms in parentheses: -(-10+2(-3x+16)), so:

-10+2(-3x+16)

determiningTheFunctionDomain
2(-3x+16)-10

We multiply parentheses

-6x+32-10

We add all the numbers together, and all the variables

-6x+22

Back to the equation:

-(-6x+22)



We add all the numbers together, and all the variables

12x-(-6x+22)+4=0

We get rid of parentheses

12x+6x-22+4=0

We add all the numbers together, and all the variables

18x-18=0

We move all terms containing x to the left, all other terms to the right

18x=18

x=18/18

x=1

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