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3x-((1-4x)/(2))=x
We move all terms to the left:
3x-((1-4x)/(2))-(x)=0
We add all the numbers together, and all the variables
3x-((-4x+1)/2)-x=0
We add all the numbers together, and all the variables
2x-((-4x+1)/2)=0
We multiply all the terms by the denominator
2x*2)-((-4x+1)=0
Wy multiply elements
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{8}=0$
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