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3x+x/5=2(x-2)
We move all terms to the left:
3x+x/5-(2(x-2))=0
We multiply all the terms by the denominator
3x*5+x-((2(x-2)))*5=0
We add all the numbers together, and all the variables
x+3x*5-((2(x-2)))*5=0
Wy multiply elements
x+15x-((2(x-2)))*5=0
We add all the numbers together, and all the variables
16x-((2(x-2)))*5=0
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