3x+x+8x=6(x-1)

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Solution for 3x+x+8x=6(x-1) equation: 



3x+x+8x=6(x-1)

We move all terms to the left:

3x+x+8x-(6(x-1))=0

We add all the numbers together, and all the variables

12x-(6(x-1))=0



We calculate terms in parentheses: -(6(x-1)), so:

6(x-1)

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

12x-6x+6=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1

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