3x+x+3/5=2

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Solution for 3x+x+3/5=2 equation: 



3x+x+3/5=2

We move all terms to the left:

3x+x+3/5-(2)=0

determiningTheFunctionDomain
3x+x-2+3/5=0

We add all the numbers together, and all the variables

4x-2+3/5=0

We multiply all the terms by the denominator


4x*5+3-2*5=0

We add all the numbers together, and all the variables

4x*5-7=0

Wy multiply elements

20x-7=0

We move all terms containing x to the left, all other terms to the right

20x=7

x=7/20

x=7/20

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