3x+8x-2(2x+4)=10

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Solution for 3x+8x-2(2x+4)=10 equation: 



3x+8x-2(2x+4)=10

We move all terms to the left:

3x+8x-2(2x+4)-(10)=0

We add all the numbers together, and all the variables

11x-2(2x+4)-10=0

We multiply parentheses

11x-4x-8-10=0

We add all the numbers together, and all the variables

7x-18=0

We move all terms containing x to the left, all other terms to the right

7x=18

x=18/7

x=2+4/7

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