3x+8=1+(2x-5)

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Solution for 3x+8=1+(2x-5) equation: 



3x+8=1+(2x-5)

We move all terms to the left:

3x+8-(1+(2x-5))=0



We calculate terms in parentheses: -(1+(2x-5)), so:

1+(2x-5)

determiningTheFunctionDomain
(2x-5)+1

We get rid of parentheses

2x-5+1

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

3x-2x+4+8=0

We add all the numbers together, and all the variables

x+12=0

We move all terms containing x to the left, all other terms to the right

x=-12

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