3x+84=(54)(3.14)+x/8

Solution for 3x+84=(54)(3.14)+x/8 equation:

3x+84=(54)(3.14)+x/8

We move all terms to the left:

3x+84-((54)(3.14)+x/8)=0

We multiply all the terms by the denominator


3x*8)-(54(3.14)+x+84*8)=0

We add all the numbers together, and all the variables

x+3x*8)-(54(3.14)=0

Wy multiply elements

24x^2+x=0

a = 24; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·24·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*24}=\frac{-2}{48}
=-1/24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*24}=\frac{0}{48}
=0
$