3x+8+4x=-8(x-6)-8(x-6)-8(13x+5)

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Solution for 3x+8+4x=-8(x-6)-8(x-6)-8(13x+5) equation: 



3x+8+4x=-8(x-6)-8(x-6)-8(13x+5)

We move all terms to the left:

3x+8+4x-(-8(x-6)-8(x-6)-8(13x+5))=0

We add all the numbers together, and all the variables

7x-(-8(x-6)-8(x-6)-8(13x+5))+8=0



We calculate terms in parentheses: -(-8(x-6)-8(x-6)-8(13x+5)), so:

-8(x-6)-8(x-6)-8(13x+5)

We multiply parentheses

-8x-8x-104x+48+48-40

We add all the numbers together, and all the variables

-120x+56

Back to the equation:

-(-120x+56)



We get rid of parentheses

7x+120x-56+8=0

We add all the numbers together, and all the variables

127x-48=0

We move all terms containing x to the left, all other terms to the right

127x=48

x=48/127

x=48/127

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