3x+7x=4(x+1)-4(4-3x)

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Solution for 3x+7x=4(x+1)-4(4-3x) equation: 



3x+7x=4(x+1)-4(4-3x)

We move all terms to the left:

3x+7x-(4(x+1)-4(4-3x))=0

We add all the numbers together, and all the variables

3x+7x-(4(x+1)-4(-3x+4))=0

We add all the numbers together, and all the variables

10x-(4(x+1)-4(-3x+4))=0



We calculate terms in parentheses: -(4(x+1)-4(-3x+4)), so:

4(x+1)-4(-3x+4)

We multiply parentheses

4x+12x+4-16

We add all the numbers together, and all the variables

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

10x-16x+12=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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