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3x+75/x=36
We move all terms to the left:
3x+75/x-(36)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
3x*x-36*x+75=0
We add all the numbers together, and all the variables
-36x+3x*x+75=0
Wy multiply elements
3x^2-36x+75=0
a = 3; b = -36; c = +75;
Δ = b2-4ac
Δ = -362-4·3·75
Δ = 396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{396}=\sqrt{36*11}=\sqrt{36}*\sqrt{11}=6\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{11}}{2*3}=\frac{36-6\sqrt{11}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{11}}{2*3}=\frac{36+6\sqrt{11}}{6} $
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