3x+7-2(x+1)=3(3x-5)

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Solution for 3x+7-2(x+1)=3(3x-5) equation: 



3x+7-2(x+1)=3(3x-5)

We move all terms to the left:

3x+7-2(x+1)-(3(3x-5))=0

We multiply parentheses

3x-2x-(3(3x-5))-2+7=0



We calculate terms in parentheses: -(3(3x-5)), so:

3(3x-5)

We multiply parentheses

9x-15

Back to the equation:

-(9x-15)



We add all the numbers together, and all the variables

x-(9x-15)+5=0

We get rid of parentheses

x-9x+15+5=0

We add all the numbers together, and all the variables

-8x+20=0

We move all terms containing x to the left, all other terms to the right

-8x=-20

x=-20/-8

x=2+1/2

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