3x+6x=9x2

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Solution for 3x+6x=9x2 equation:



3x+6x=9x^2
We move all terms to the left:
3x+6x-(9x^2)=0
determiningTheFunctionDomain -9x^2+3x+6x=0
We add all the numbers together, and all the variables
-9x^2+9x=0
a = -9; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-9)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-9}=\frac{-18}{-18} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-9}=\frac{0}{-18} =0 $

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