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3x+6=5(x+1)-3+7x
We move all terms to the left:
3x+6-(5(x+1)-3+7x)=0
We calculate terms in parentheses: -(5(x+1)-3+7x), so:We get rid of parentheses
5(x+1)-3+7x
determiningTheFunctionDomain 5(x+1)+7x-3
We add all the numbers together, and all the variables
7x+5(x+1)-3
We multiply parentheses
7x+5x+5-3
We add all the numbers together, and all the variables
12x+2
Back to the equation:
-(12x+2)
3x-12x-2+6=0
We add all the numbers together, and all the variables
-9x+4=0
We move all terms containing x to the left, all other terms to the right
-9x=-4
x=-4/-9
x=4/9
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