3x+6=3(4x-4)-10x

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Solution for 3x+6=3(4x-4)-10x equation: 



3x+6=3(4x-4)-10x

We move all terms to the left:

3x+6-(3(4x-4)-10x)=0



We calculate terms in parentheses: -(3(4x-4)-10x), so:

3(4x-4)-10x

We add all the numbers together, and all the variables

-10x+3(4x-4)

We multiply parentheses

-10x+12x-12

We add all the numbers together, and all the variables

2x-12

Back to the equation:

-(2x-12)



We get rid of parentheses

3x-2x+12+6=0

We add all the numbers together, and all the variables

x+18=0

We move all terms containing x to the left, all other terms to the right

x=-18

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