3x+67+108=(4x+10)

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Solution for 3x+67+108=(4x+10) equation: 



3x+67+108=(4x+10)

We move all terms to the left:

3x+67+108-((4x+10))=0

We add all the numbers together, and all the variables

3x-((4x+10))+175=0



We calculate terms in parentheses: -((4x+10)), so:

(4x+10)

We get rid of parentheses

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

3x-4x-10+175=0

We add all the numbers together, and all the variables

-1x+165=0

We move all terms containing x to the left, all other terms to the right

-x=-165

x=-165/-1

x=+165

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