3x+6(x-2)+4(x+3)=5x-2(x-1)

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Solution for 3x+6(x-2)+4(x+3)=5x-2(x-1) equation: 



3x+6(x-2)+4(x+3)=5x-2(x-1)

We move all terms to the left:

3x+6(x-2)+4(x+3)-(5x-2(x-1))=0

We multiply parentheses

3x+6x+4x-(5x-2(x-1))-12+12=0



We calculate terms in parentheses: -(5x-2(x-1)), so:

5x-2(x-1)

We multiply parentheses

5x-2x+2

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

13x-(3x+2)=0

We get rid of parentheses

13x-3x-2=0

We add all the numbers together, and all the variables

10x-2=0

We move all terms containing x to the left, all other terms to the right

10x=2

x=2/10

x=1/5

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